# How to multiply two 2-digit numbers within seconds using a math trick in mind?

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**Example: 1**

Suppose you want to multiply 20 with 22 (20 * 22)

You don't need to apply the usual way which will take a long time to do this calculation in a rough paper. Just use this trick in the mind itself and the outcome of the multiplication will still be accurate.

What you need to do?

So, you have to multiply 20 with 22?

**Step1**: First, take the 2nd digit of each number and multiply them.

2nd digit of 20 is 0.

2nd digit of 22 is 2.

So, lets multiply 0 * 2 = 0 (**Remember this 1st outcome number**)

**Step 2**: Now, we need to do the cross-multiplication of the two numbers. That is, multiple 1st digit of the 1st number with the 2nd digit of the 2nd number and vice versa and then add the two numbers that come.

This will look something like this

2 * 2 + 2 * 0 = 4 (**Remember this 2nd outcome number**)

**Step 3**: Now finally we need to multiply the first digit of each number as below

2 * 2 = 4 (**Remember this 3rd outcome number**)

To get the final answer simply write the 3 outcome numbers in the sequence as below from step 1, step 2 and step 3.

3rd outcome number - 2nd outcome number - 1st outcome number

440 (this is your quick answer).

**Example 2: **

This example 2 will be a little bit tricky as the outcome of the cross-multiplication in 2nd step will be greater than 10 and so we have to carry.

Suppose you want to multiply 34 with 22 (34 * 22).

We have to follow the same steps as in **example 1**

**Step 1**: First, take the 2nd digit of each number and multiply them

4 * 2 = 8 (**Remember this 1st outcome number**)

**Step 2** : Now, we need to do the cross-multiplication of the two numbers. That is, multiple 1st digit of the 1st number with the 2nd digit of the 2nd number and vice versa and then add the two numbers that come.

This will look something like this

3 * 2 + 4 * 2 = 14 (the outcome)

But we will write outcome as 4 (2nd digit of the outcome) and carry the first digit which is 1

So, 4 (**Remember this 2nd outcome number + carry (1)**)

**Step 3**: Now finally we need to multiply the first digit of each number as below and add the carry from step 2 as above.

3 * 2 = 6 (+ 1 carry)= 7 (**Remember this 3rd outcome number**)

To get the final and accurate answer simply write the 3 outcome numbers in the sequence as below from step 1, step 2 and step 3.

3rd outcome number - 2nd outcome number - 1st outcome number

748 (**this is your final answer**).

So, there is no need of even using a calculator as this easy math trick can be done in the mind.

**Example 3 :**

This example 3 is more complicated than the above two examples as it involves carry at two places.

Suppose you want to multiply 35 with 25 (35 * 25)

**Step 1:** First, take the 2nd digit of each number and multiply them

5 * 5 = 25 (this is outcome)

But we write outcome as 5 (2nd digit) and carry the first digit which is 2.

So, 5 (Remember this 1st outcome number and carry as 2)

**Step 2:** Now, we need to do the cross-multiplication of the two numbers. That is, multiple 1st digit of the 1st number with the 2nd digit of the 2nd number and vice versa and then add the two numbers that come.

This will look something like this

3 * 5 + 5 * 2 = 25 + (2 as carry)= 27 (the outcome)

But we will write outcome as 7 (2nd digit of above outcome) and carry the first digit which is 2

So, 7 (**Remember this 2nd outcome number + carry (2)**)

**Step 3:** Now finally we need to multiply the first digit of each number as below and add the carry from step 2 as above.

3 * 2 = 6 (+ 2 carry)= 8 (Remember this 3rd outcome number).

To get the final and accurate answer simply write the 3 outcome numbers in the sequence as below from step 1, step 2 and step 3.

3rd outcome number - 2nd outcome number - 1st outcome number.

875 (this is your final answer).

This was possible through Vedic Maths. This trick works for all 2-digits multiplications. You can try it on your own with different 2 digit numbers.

Hope you enjoyed it and find it useful.

Here is a easier way to multiply two 3-digit numbers

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**Written by:** Rajesh Bihani ( Find me on Google+ )